Nilai dari [² (3x²-8x +1) dx adalah...
Jawaban:
-4
Penjelasan dengan langkah-langkah:
[tex] { \int}_{1} ^{2} \: 3 {x}^{2} - 8x + 1 \: dx \\ \frac{3}{3} {x}^{3} - \frac{8}{2} {x}^{2} + x \: | _{1} ^{2} \\ = ( {2}^{3} - 4(2) {}^{2} + 2) - ( {1}^{3} - 4(1) {}^{2} + 1) \\ = (8 - 16 + 2) - (1 - 4 + 1) \\ = ( - 6) - ( - 2) \\ = - 6 + 2 \\ = - 4[/tex]
[answer.2.content]
